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Pyranose ring structure of glucose is due to hemiacetal formation between :a.) ${C_1}$ and ${C_5}$b.) ${C_1}$ and ${C_4}$c.) ${C_1}$ and ${C_3}$d.) ${C_2}$ and ${C_4}$
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SOLVED: 3) The linear form of glucose can cyclize to form cyclized carbohydrate For the following reaction: In the linear form of glucose, label the electrophilic atom (E) and nucleophilic atom (N)
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